What are the solutions to the equation x^4+8x^2+16=0 ?

The solutions to the equation x^4+8x^2+16=0 are x=2i,x=-2i

Find the zeros of x^4+8x^2+16=0

The zeros of x^4+8x^2+16=0 are x=2i,x=-2i

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x^{4} + 8 x^{2} + 16 = 0

x = 2 i, x = - 2 i

Solution steps

x^{4} + 8 x^{2} + 16 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} + 8 u + 16 = 0

Solve

u^{2} + 8 u + 16 = 0 : u = - 4

u = - 4

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = - 4 : x = 2 i, x = - 2 i

The solutions are

x = 2 i, x = - 2 i

x, x^{3} y = - 4

x + 1.5 x^{2} + 9 x^{4} = 0

x, 8 x^{3} - y = 0

0 = \frac{1}{2} x^{3} - x

- x^{3} + 6 x^{2} - 12 x + 8 = 0

What are the solutions to the equation x^4+8x^2+16=0 ?
The solutions to the equation x^4+8x^2+16=0 are x=2i,x=-2i
Find the zeros of x^4+8x^2+16=0
The zeros of x^4+8x^2+16=0 are x=2i,x=-2i