What are the solutions to the equation 8x^3-2x=0 ?

The solutions to the equation 8x^3-2x=0 are x=0,x=-1/2 ,x= 1/2

Find the zeros of 8x^3-2x=0

The zeros of 8x^3-2x=0 are x=0,x=-1/2 ,x= 1/2

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8 x^{3} - 2 x = 0

x = 0, x = - \frac{1}{2}, x = \frac{1}{2}

Decimal Notation

x = 0, x = - 0.5, x = 0.5

Solution steps

8 x^{3} - 2 x = 0

Factor

8 x^{3} - 2 x : 2 x (2 x + 1) (2 x - 1)

2 x (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 0, x = - \frac{1}{2}, x = \frac{1}{2}

r^{3} = 125

x^{9} = 1 2^{2} \cdot 1 2^{7}

x^{3} + 4 x^{2} + 9 x + 36 = 0

x, y = 3 x^{3} + 7

3 x^{3} - 4 x^{2} - 5 x + 2 = 0

What are the solutions to the equation 8x^3-2x=0 ?
The solutions to the equation 8x^3-2x=0 are x=0,x=-1/2 ,x= 1/2
Find the zeros of 8x^3-2x=0
The zeros of 8x^3-2x=0 are x=0,x=-1/2 ,x= 1/2