What are the solutions to the equation (2x+2)(3x-6)(4x-12)=0 ?

The solutions to the equation (2x+2)(3x-6)(4x-12)=0 are x=-1,x=2,x=3

Find the zeros of (2x+2)(3x-6)(4x-12)=0

The zeros of (2x+2)(3x-6)(4x-12)=0 are x=-1,x=2,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x + 2) (3 x - 6) (4 x - 12) = 0

x = - 1, x = 2, x = 3

Solution steps

(2 x + 2) (3 x - 6) (4 x - 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 2 = 0 or 3 x - 6 = 0 or 4 x - 12 = 0

Solve

2 x + 2 = 0 : x = - 1

Solve

3 x - 6 = 0 : x = 2

Solve

4 x - 12 = 0 : x = 3

The solutions are

x = - 1, x = 2, x = 3

p^{3} = 125

(x - 1) (x + 2) (x - 3) = 0

(z + 1)^{4} = (z - 1)^{4}

y^{3} = 125

y^{3} = \frac{27}{1000}

What are the solutions to the equation (2x+2)(3x-6)(4x-12)=0 ?
The solutions to the equation (2x+2)(3x-6)(4x-12)=0 are x=-1,x=2,x=3
Find the zeros of (2x+2)(3x-6)(4x-12)=0
The zeros of (2x+2)(3x-6)(4x-12)=0 are x=-1,x=2,x=3