What are the solutions to the equation -3x(2x-1)(x+6)^2=0 ?

The solutions to the equation -3x(2x-1)(x+6)^2=0 are x=0,x= 1/2 ,x=-6

Find the zeros of -3x(2x-1)(x+6)^2=0

The zeros of -3x(2x-1)(x+6)^2=0 are x=0,x= 1/2 ,x=-6

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- 3 x (2 x - 1) (x + 6)^{2} = 0

x = 0, x = \frac{1}{2}, x = - 6

Decimal Notation

x = 0, x = 0.5, x = - 6

Solution steps

- 3 x (2 x - 1) (x + 6)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 1 = 0 or x + 6 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 6 = 0 : x = - 6

The solutions are

x = 0, x = \frac{1}{2}, x = - 6

45 = 4 y^{3} - 3

x^{4} - 3 x^{3} - 9 x^{2} + 23 x - 12 = 0

x^{3} + 5 x^{2} - 9 x - 45 = 0

x^{3} - 6 x^{2} - 4 x + 24 = 0

x^{4} - 9 x^{2} - 12 x - 4 = 0

What are the solutions to the equation -3x(2x-1)(x+6)^2=0 ?
The solutions to the equation -3x(2x-1)(x+6)^2=0 are x=0,x= 1/2 ,x=-6
Find the zeros of -3x(2x-1)(x+6)^2=0
The zeros of -3x(2x-1)(x+6)^2=0 are x=0,x= 1/2 ,x=-6