What are the solutions to the equation x^4-9x^2-12x-4=0 ?

The solutions to the equation x^4-9x^2-12x-4=0 are x=-1,x=-2,x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2

Find the zeros of x^4-9x^2-12x-4=0

The zeros of x^4-9x^2-12x-4=0 are x=-1,x=-2,x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2

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x^{4} - 9 x^{2} - 12 x - 4 = 0

x = - 1, x = - 2, x = \frac{3 + 17}{2}, x = \frac{3 - 17}{2}

Decimal Notation

x = - 1, x = - 2, x = 3.56155 \dots, x = - 0.56155 \dots

Solution steps

x^{4} - 9 x^{2} - 12 x - 4 = 0

Factor

x^{4} - 9 x^{2} - 12 x - 4 : (x + 1) (x + 2) (x^{2} - 3 x - 2)

(x + 1) (x + 2) (x^{2} - 3 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 2 = 0 or x^{2} - 3 x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} - 3 x - 2 = 0 : x = \frac{3 + 17}{2}, x = \frac{3 - 17}{2}

The solutions are

x = - 1, x = - 2, x = \frac{3 + 17}{2}, x = \frac{3 - 17}{2}

x^{6} - 28 x + 27 = 0

x^{4} - 16 x^{2} + 63 = 0

x^{3} - 15 x + 1 = 0

x, x^{3} + y^{5} = 4

x^{3} + 3 x^{2} - 2 x - 5 = 0

What are the solutions to the equation x^4-9x^2-12x-4=0 ?
The solutions to the equation x^4-9x^2-12x-4=0 are x=-1,x=-2,x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2
Find the zeros of x^4-9x^2-12x-4=0
The zeros of x^4-9x^2-12x-4=0 are x=-1,x=-2,x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2