What are the solutions to the equation 6x^4-25x^3+12x^2+25x+6=0 ?

The solutions to the equation 6x^4-25x^3+12x^2+25x+6=0 are x=2,x=3,x=-1/3 ,x=-1/2

Find the zeros of 6x^4-25x^3+12x^2+25x+6=0

The zeros of 6x^4-25x^3+12x^2+25x+6=0 are x=2,x=3,x=-1/3 ,x=-1/2

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6 x^{4} - 25 x^{3} + 12 x^{2} + 25 x + 6 = 0

x = 2, x = 3, x = - \frac{1}{3}, x = - \frac{1}{2}

Decimal Notation

x = 2, x = 3, x = - 0.33333 \dots, x = - 0.5

Solution steps

6 x^{4} - 25 x^{3} + 12 x^{2} + 25 x + 6 = 0

Factor

6 x^{4} - 25 x^{3} + 12 x^{2} + 25 x + 6 : (x - 2) (x - 3) (3 x + 1) (2 x + 1)

(x - 2) (x - 3) (3 x + 1) (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 3 = 0 or 3 x + 1 = 0 or 2 x + 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 3 = 0 : x = 3

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions are

x = 2, x = 3, x = - \frac{1}{3}, x = - \frac{1}{2}

- x^{3} + 3 x^{2} = 0

x^{7} - 1 = 0

x^{5} = 9 x^{3}

(y - 2)^{4} = 0

- x^{3} + x^{2} + 4 x + 6 = 0

What are the solutions to the equation 6x^4-25x^3+12x^2+25x+6=0 ?
The solutions to the equation 6x^4-25x^3+12x^2+25x+6=0 are x=2,x=3,x=-1/3 ,x=-1/2
Find the zeros of 6x^4-25x^3+12x^2+25x+6=0
The zeros of 6x^4-25x^3+12x^2+25x+6=0 are x=2,x=3,x=-1/3 ,x=-1/2