What are the solutions to the equation -x^3+x^2+4x+6=0 ?

The solutions to the equation -x^3+x^2+4x+6=0 are x=3,x=-1+i,x=-1-i

Find the zeros of -x^3+x^2+4x+6=0

The zeros of -x^3+x^2+4x+6=0 are x=3,x=-1+i,x=-1-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{3} + x^{2} + 4 x + 6 = 0

x = 3, x = - 1 + i, x = - 1 - i

Solution steps

- x^{3} + x^{2} + 4 x + 6 = 0

Factor

- x^{3} + x^{2} + 4 x + 6 : - (x - 3) (x^{2} + 2 x + 2)

- (x - 3) (x^{2} + 2 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} + 2 x + 2 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} + 2 x + 2 = 0 : x = - 1 + i, x = - 1 - i

The solutions are

x = 3, x = - 1 + i, x = - 1 - i

r, x = \frac{4}{3} π r^{3}

x^{3} + 3 x^{2} - 3 x - 9 = 0

(x + 1) (x - 2) (x + 3) = 0

x^{2} (x + 1) - 64 (x + 1) = 0

x^{3} + 6 x^{2} = 16 x

What are the solutions to the equation -x^3+x^2+4x+6=0 ?
The solutions to the equation -x^3+x^2+4x+6=0 are x=3,x=-1+i,x=-1-i
Find the zeros of -x^3+x^2+4x+6=0
The zeros of -x^3+x^2+4x+6=0 are x=3,x=-1+i,x=-1-i