What are the solutions to the equation -x^3+4x^2-4x=0 ?

The solutions to the equation -x^3+4x^2-4x=0 are x=0,x=2

Find the zeros of -x^3+4x^2-4x=0

The zeros of -x^3+4x^2-4x=0 are x=0,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{3} + 4 x^{2} - 4 x = 0

x = 0, x = 2

Solution steps

- x^{3} + 4 x^{2} - 4 x = 0

Factor

- x^{3} + 4 x^{2} - 4 x : - x (x - 2)^{2}

- x (x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 2

x^{3} - x + 6 = 0

98 x - 49 = 2 x^{3} - x^{2}

x^{4} = - 256

36 x^{4} - 83 x^{2} + 35 = 0

x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 = 0

What are the solutions to the equation -x^3+4x^2-4x=0 ?
The solutions to the equation -x^3+4x^2-4x=0 are x=0,x=2
Find the zeros of -x^3+4x^2-4x=0
The zeros of -x^3+4x^2-4x=0 are x=0,x=2