What are the solutions to the equation (4x-3)(3x-1)(2x-2pi)=0 ?

The solutions to the equation (4x-3)(3x-1)(2x-2pi)=0 are x= 3/4 ,x= 1/3 ,x=pi

Find the zeros of (4x-3)(3x-1)(2x-2pi)=0

The zeros of (4x-3)(3x-1)(2x-2pi)=0 are x= 3/4 ,x= 1/3 ,x=pi

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(4 x - 3) (3 x - 1) (2 x - 2 π) = 0

x = \frac{3}{4}, x = \frac{1}{3}, x = π

Decimal Notation

x = 0.75, x = 0.33333 \dots, x = 3.14159 \dots

Solution steps

(4 x - 3) (3 x - 1) (2 x - 2 π) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x - 3 = 0 or 3 x - 1 = 0 or 2 x - 2 π = 0

Solve

4 x - 3 = 0 : x = \frac{3}{4}

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

2 x - 2 π = 0 : x = π

The solutions are

x = \frac{3}{4}, x = \frac{1}{3}, x = π

16 x^{4} - 81 = 0

x^{3} + 4 x^{2} - 2 x = 0

x^{3} + x^{2} + 2 x - 3 = 0

x^{4} + 4 x - 1 = 0

64 = x^{3}

What are the solutions to the equation (4x-3)(3x-1)(2x-2pi)=0 ?
The solutions to the equation (4x-3)(3x-1)(2x-2pi)=0 are x= 3/4 ,x= 1/3 ,x=pi
Find the zeros of (4x-3)(3x-1)(2x-2pi)=0
The zeros of (4x-3)(3x-1)(2x-2pi)=0 are x= 3/4 ,x= 1/3 ,x=pi