What are the solutions to the equation x(x^2+1)=0 ?

The solutions to the equation x(x^2+1)=0 are x=0,x=i,x=-i

Find the zeros of x(x^2+1)=0

The zeros of x(x^2+1)=0 are x=0,x=i,x=-i

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x (x^{2} + 1) = 0

x = 0, x = i, x = - i

Solution steps

x (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 1 = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = 0, x = i, x = - i

x (x - 1) (x + 2) = \frac{1}{6} x

z^{7} = (- 1 + 2 j)

x^{4} + x^{2} = 12

2 x^{3} - 24 x^{2} + 70 x = 0

x^{4} - 12 x^{2} + 35 = 0

What are the solutions to the equation x(x^2+1)=0 ?
The solutions to the equation x(x^2+1)=0 are x=0,x=i,x=-i
Find the zeros of x(x^2+1)=0
The zeros of x(x^2+1)=0 are x=0,x=i,x=-i