What are the solutions to the equation -x(x^2-49)(16x^2-25)=0 ?

The solutions to the equation -x(x^2-49)(16x^2-25)=0 are x=0,x=-7,x=7,x=-5/4 ,x= 5/4

Find the zeros of -x(x^2-49)(16x^2-25)=0

The zeros of -x(x^2-49)(16x^2-25)=0 are x=0,x=-7,x=7,x=-5/4 ,x= 5/4

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- x (x^{2} - 49) (16 x^{2} - 25) = 0

x = 0, x = - 7, x = 7, x = - \frac{5}{4}, x = \frac{5}{4}

Decimal Notation

x = 0, x = - 7, x = 7, x = - 1.25, x = 1.25

Solution steps

- x (x^{2} - 49) (16 x^{2} - 25) = 0

Factor

- x (x^{2} - 49) (16 x^{2} - 25) : - x (x + 7) (x - 7) (4 x + 5) (4 x - 5)

- x (x + 7) (x - 7) (4 x + 5) (4 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 7 = 0 or x - 7 = 0 or 4 x + 5 = 0 or 4 x - 5 = 0

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

Solve

4 x - 5 = 0 : x = \frac{5}{4}

The solutions are

x = 0, x = - 7, x = 7, x = - \frac{5}{4}, x = \frac{5}{4}

x^{3} = 64 x

x^{3} + 5 x^{2} - 14 x = 0

x^{3} + 3 x^{2} - 5 x - 15 = 0

x^{4} - x^{3} + x^{2} - x = 0

x^{3} + 3 x^{2} - 16 x - 48 = 0

What are the solutions to the equation -x(x^2-49)(16x^2-25)=0 ?
The solutions to the equation -x(x^2-49)(16x^2-25)=0 are x=0,x=-7,x=7,x=-5/4 ,x= 5/4
Find the zeros of -x(x^2-49)(16x^2-25)=0
The zeros of -x(x^2-49)(16x^2-25)=0 are x=0,x=-7,x=7,x=-5/4 ,x= 5/4