What are the solutions to the equation 3(x+8)(x^2-81)=0 ?

The solutions to the equation 3(x+8)(x^2-81)=0 are x=-8,x=-9,x=9

Find the zeros of 3(x+8)(x^2-81)=0

The zeros of 3(x+8)(x^2-81)=0 are x=-8,x=-9,x=9

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3 (x + 8) (x^{2} - 81) = 0

x = - 8, x = - 9, x = 9

Solution steps

3 (x + 8) (x^{2} - 81) = 0

Factor

3 (x + 8) (x^{2} - 81) : 3 (x + 8) (x + 9) (x - 9)

3 (x + 8) (x + 9) (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 8 = 0 or x + 9 = 0 or x - 9 = 0

Solve

x + 8 = 0 : x = - 8

Solve

x + 9 = 0 : x = - 9

Solve

x - 9 = 0 : x = 9

The solutions are

x = - 8, x = - 9, x = 9

x^{3} - x^{2} + 2 x - 2 = 0

x^{4} + 7 x^{2} - 144 = 0

x^{3} + 3 x^{2} + 2 x + 6 = 0

x^{4} = \frac{1}{16}

x^{4} + 2 x^{2} + x = 0

What are the solutions to the equation 3(x+8)(x^2-81)=0 ?
The solutions to the equation 3(x+8)(x^2-81)=0 are x=-8,x=-9,x=9
Find the zeros of 3(x+8)(x^2-81)=0
The zeros of 3(x+8)(x^2-81)=0 are x=-8,x=-9,x=9