What are the solutions to the equation -x^3+12x^2-21x-98=0 ?

The solutions to the equation -x^3+12x^2-21x-98=0 are x=-2,x=7

Find the zeros of -x^3+12x^2-21x-98=0

The zeros of -x^3+12x^2-21x-98=0 are x=-2,x=7

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- x^{3} + 12 x^{2} - 21 x - 98 = 0

x = - 2, x = 7

Solution steps

- x^{3} + 12 x^{2} - 21 x - 98 = 0

Factor

- x^{3} + 12 x^{2} - 21 x - 98 : - (x + 2) (x - 7)^{2}

- (x + 2) (x - 7)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 7 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 7 = 0 : x = 7

The solutions are

x = - 2, x = 7

x^{3} - x^{2} = 4

5 x^{3} + 6 x^{2} - 18 x + 5 = 0

x^{4} - 2 x^{2} - 24 = 0

- x^{3} - x^{2} + x + 1 = 0

x^{3} - 6 x^{2} - 27 x = 0

What are the solutions to the equation -x^3+12x^2-21x-98=0 ?
The solutions to the equation -x^3+12x^2-21x-98=0 are x=-2,x=7
Find the zeros of -x^3+12x^2-21x-98=0
The zeros of -x^3+12x^2-21x-98=0 are x=-2,x=7