What are the solutions to the equation 6x^3+7x^2-9x+2=0 ?

The solutions to the equation 6x^3+7x^2-9x+2=0 are x=-2,x= 1/3 ,x= 1/2

Find the zeros of 6x^3+7x^2-9x+2=0

The zeros of 6x^3+7x^2-9x+2=0 are x=-2,x= 1/3 ,x= 1/2

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6 x^{3} + 7 x^{2} - 9 x + 2 = 0

x = - 2, x = \frac{1}{3}, x = \frac{1}{2}

Decimal Notation

x = - 2, x = 0.33333 \dots, x = 0.5

Solution steps

6 x^{3} + 7 x^{2} - 9 x + 2 = 0

Factor

6 x^{3} + 7 x^{2} - 9 x + 2 : (x + 2) (3 x - 1) (2 x - 1)

(x + 2) (3 x - 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or 3 x - 1 = 0 or 2 x - 1 = 0

Solve

x + 2 = 0 : x = - 2

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = - 2, x = \frac{1}{3}, x = \frac{1}{2}

x^{4} - 30 x^{2} + 125 = 0

x^{3} - 3 x^{2} - 9 x + 27 = 0

3 x^{3} + x^{2} - 48 x = 16

- x^{3} = 0

x^{3} - 6 x = 0

What are the solutions to the equation 6x^3+7x^2-9x+2=0 ?
The solutions to the equation 6x^3+7x^2-9x+2=0 are x=-2,x= 1/3 ,x= 1/2
Find the zeros of 6x^3+7x^2-9x+2=0
The zeros of 6x^3+7x^2-9x+2=0 are x=-2,x= 1/3 ,x= 1/2