What are the solutions to the equation x^3-3x^2-9x+27=0 ?

The solutions to the equation x^3-3x^2-9x+27=0 are x=3,x=-3

Find the zeros of x^3-3x^2-9x+27=0

The zeros of x^3-3x^2-9x+27=0 are x=3,x=-3

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x^{3} - 3 x^{2} - 9 x + 27 = 0

x = 3, x = - 3

Solution steps

x^{3} - 3 x^{2} - 9 x + 27 = 0

Factor

x^{3} - 3 x^{2} - 9 x + 27 : (x - 3)^{2} (x + 3)

(x - 3)^{2} (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 3 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 3, x = - 3

3 x^{3} + x^{2} - 48 x = 16

- x^{3} = 0

x^{3} - 6 x = 0

12 x^{2} - 9 x - 3 x^{3} = 0

(x^{3} - 1) = 0

What are the solutions to the equation x^3-3x^2-9x+27=0 ?
The solutions to the equation x^3-3x^2-9x+27=0 are x=3,x=-3
Find the zeros of x^3-3x^2-9x+27=0
The zeros of x^3-3x^2-9x+27=0 are x=3,x=-3