What are the solutions to the equation 3x^4+2=5x^2 ?

The solutions to the equation 3x^4+2=5x^2 are x=1,x=-1,x=sqrt(2/3),x=-sqrt(2/3)

Find the zeros of 3x^4+2=5x^2

The zeros of 3x^4+2=5x^2 are x=1,x=-1,x=sqrt(2/3),x=-sqrt(2/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{4} + 2 = 5 x^{2}

x = 1, x = - 1, x = \frac{2}{3}, x = - \frac{2}{3}

Decimal Notation

x = 1, x = - 1, x = 0.81649 \dots, x = - 0.81649 \dots

Solution steps

3 x^{4} + 2 = 5 x^{2}

Move

5 x^{2}

to the left side

3 x^{4} + 2 - 5 x^{2} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

3 x^{4} - 5 x^{2} + 2 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

3 u^{2} - 5 u + 2 = 0

Solve

3 u^{2} - 5 u + 2 = 0 : u = 1, u = \frac{2}{3}

u = 1, u = \frac{2}{3}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 1 : x = 1, x = - 1

Solve

x^{2} = \frac{2}{3} : x = \frac{2}{3}, x = - \frac{2}{3}

The solutions are

x = 1, x = - 1, x = \frac{2}{3}, x = - \frac{2}{3}

x + 6 = x^{3}

- x^{3} + 2 x^{2} - x = 0

27 x^{4} + 60 x^{2} = 32

3 (x - 1) (x + 2) (x - 4) = 0

x^{4} - x^{3} + x = 1

What are the solutions to the equation 3x^4+2=5x^2 ?
The solutions to the equation 3x^4+2=5x^2 are x=1,x=-1,x=sqrt(2/3),x=-sqrt(2/3)
Find the zeros of 3x^4+2=5x^2
The zeros of 3x^4+2=5x^2 are x=1,x=-1,x=sqrt(2/3),x=-sqrt(2/3)