What are the solutions to the equation 8x^3-14x^2+7x-1=0 ?

The solutions to the equation 8x^3-14x^2+7x-1=0 are x=1,x= 1/4 ,x= 1/2

Find the zeros of 8x^3-14x^2+7x-1=0

The zeros of 8x^3-14x^2+7x-1=0 are x=1,x= 1/4 ,x= 1/2

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8 x^{3} - 14 x^{2} + 7 x - 1 = 0

x = 1, x = \frac{1}{4}, x = \frac{1}{2}

Decimal Notation

x = 1, x = 0.25, x = 0.5

Solution steps

8 x^{3} - 14 x^{2} + 7 x - 1 = 0

Factor

8 x^{3} - 14 x^{2} + 7 x - 1 : (x - 1) (4 x - 1) (2 x - 1)

(x - 1) (4 x - 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 4 x - 1 = 0 or 2 x - 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 1, x = \frac{1}{4}, x = \frac{1}{2}

x^{4} - 10 x^{2} = - 9

z^{3} + 64 = 0

x^{3} + 2 x - 8 = 0

(x - 1)^{3} + 2 = 0

8 x^{4} - 18 x^{2} = 0

What are the solutions to the equation 8x^3-14x^2+7x-1=0 ?
The solutions to the equation 8x^3-14x^2+7x-1=0 are x=1,x= 1/4 ,x= 1/2
Find the zeros of 8x^3-14x^2+7x-1=0
The zeros of 8x^3-14x^2+7x-1=0 are x=1,x= 1/4 ,x= 1/2