What are the solutions to the equation p^3=27 ?

The solutions to the equation p^3=27 are p=3,p=-3/2+(3sqrt(3))/2 i,p=-3/2-(3sqrt(3))/2 i

Find the zeros of p^3=27

The zeros of p^3=27 are p=3,p=-3/2+(3sqrt(3))/2 i,p=-3/2-(3sqrt(3))/2 i

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p^{3} = 27

p = 3, p = - \frac{3}{2} + \frac{3 3}{2} i, p = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

p^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

p = 3, p = - \frac{3}{2} + \frac{3 3}{2} i, p = - \frac{3}{2} - \frac{3 3}{2} i

4 x^{3} - x^{2} - 56 x + 14 = 0

(8 x - 7) (x^{2} - 5) = 0

2 x^{3} + 9 x^{2} + 13 x + 6 = 0

x^{4} + 6 x^{2} + 8 = 0

4 x^{3} + 16 x^{2} + 12 x = 0

What are the solutions to the equation p^3=27 ?
The solutions to the equation p^3=27 are p=3,p=-3/2+(3sqrt(3))/2 i,p=-3/2-(3sqrt(3))/2 i
Find the zeros of p^3=27
The zeros of p^3=27 are p=3,p=-3/2+(3sqrt(3))/2 i,p=-3/2-(3sqrt(3))/2 i