What are the solutions to the equation 8y^3-216=0 ?

The solutions to the equation 8y^3-216=0 are y=3,y=-3/2+(3sqrt(3))/2 i,y=-3/2-(3sqrt(3))/2 i

Find the zeros of 8y^3-216=0

The zeros of 8y^3-216=0 are y=3,y=-3/2+(3sqrt(3))/2 i,y=-3/2-(3sqrt(3))/2 i

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8 y^{3} - 216 = 0

y = 3, y = - \frac{3}{2} + \frac{3 3}{2} i, y = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

8 y^{3} - 216 = 0

Move

216

to the right side

8 y^{3} = 216

Divide both sides by

8

y^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

y = 3, y = - \frac{3}{2} + \frac{3 3}{2} i, y = - \frac{3}{2} - \frac{3 3}{2} i

x^{4} - 36 x^{2} + 35 = 0

(x^{2} - 1)^{3} = 0

x^{6} - 729 = 0

(8 x^{2} - 10 x - 3) (2 x + b) = 0

x^{5} = 121 x^{3}

What are the solutions to the equation 8y^3-216=0 ?
The solutions to the equation 8y^3-216=0 are y=3,y=-3/2+(3sqrt(3))/2 i,y=-3/2-(3sqrt(3))/2 i
Find the zeros of 8y^3-216=0
The zeros of 8y^3-216=0 are y=3,y=-3/2+(3sqrt(3))/2 i,y=-3/2-(3sqrt(3))/2 i