What are the solutions to the equation (8x^2-10x-3)(2x+b)=0 ?

The solutions to the equation (8x^2-10x-3)(2x+b)=0 are x=-1/4 ,x= 3/2 ,x=-b/2

Find the zeros of (8x^2-10x-3)(2x+b)=0

The zeros of (8x^2-10x-3)(2x+b)=0 are x=-1/4 ,x= 3/2 ,x=-b/2

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(8 x^{2} - 10 x - 3) (2 x + b) = 0

x = - \frac{1}{4}, x = \frac{3}{2}, x = - \frac{b}{2}

Solution steps

(8 x^{2} - 10 x - 3) (2 x + b) = 0

Factor

(8 x^{2} - 10 x - 3) (2 x + b) : (4 x + 1) (2 x - 3) (2 x + b)

(4 x + 1) (2 x - 3) (2 x + b) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 1 = 0 or 2 x - 3 = 0 or 2 x + b = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

2 x + b = 0 : x = - \frac{b}{2}

The solutions are

x = - \frac{1}{4}, x = \frac{3}{2}, x = - \frac{b}{2}

x^{5} = 121 x^{3}

d^{3} = 27

9 x^{4} - 46 x^{2} + 5 = 0

x^{5} - x + 1 = 0

32 x^{3} - 8 x^{7} = 0

What are the solutions to the equation (8x^2-10x-3)(2x+b)=0 ?
The solutions to the equation (8x^2-10x-3)(2x+b)=0 are x=-1/4 ,x= 3/2 ,x=-b/2
Find the zeros of (8x^2-10x-3)(2x+b)=0
The zeros of (8x^2-10x-3)(2x+b)=0 are x=-1/4 ,x= 3/2 ,x=-b/2