What are the solutions to the equation 4x^3-20x^2+23x-7=0 ?

The solutions to the equation 4x^3-20x^2+23x-7=0 are x=1,x= 1/2 ,x= 7/2

Find the zeros of 4x^3-20x^2+23x-7=0

The zeros of 4x^3-20x^2+23x-7=0 are x=1,x= 1/2 ,x= 7/2

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4 x^{3} - 20 x^{2} + 23 x - 7 = 0

x = 1, x = \frac{1}{2}, x = \frac{7}{2}

Decimal Notation

x = 1, x = 0.5, x = 3.5

Solution steps

4 x^{3} - 20 x^{2} + 23 x - 7 = 0

Factor

4 x^{3} - 20 x^{2} + 23 x - 7 : (x - 1) (2 x - 1) (2 x - 7)

(x - 1) (2 x - 1) (2 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x - 1 = 0 or 2 x - 7 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

2 x - 7 = 0 : x = \frac{7}{2}

The solutions are

x = 1, x = \frac{1}{2}, x = \frac{7}{2}

3 x^{4} = 648 x

- 2 x^{4} + 7 = 3 x - 2

3 x^{3} + 4 x^{2} = 27 x + 36

a^{10} = - 3 \cdot (- 2^{(10 - 1)})

x^{5} + 2 x - 3 = 0

What are the solutions to the equation 4x^3-20x^2+23x-7=0 ?
The solutions to the equation 4x^3-20x^2+23x-7=0 are x=1,x= 1/2 ,x= 7/2
Find the zeros of 4x^3-20x^2+23x-7=0
The zeros of 4x^3-20x^2+23x-7=0 are x=1,x= 1/2 ,x= 7/2