What are the solutions to the equation 2x(2x+9)(16x^2-9)=0 ?

The solutions to the equation 2x(2x+9)(16x^2-9)=0 are x=0,x=-9/2 ,x=-3/4 ,x= 3/4

Find the zeros of 2x(2x+9)(16x^2-9)=0

The zeros of 2x(2x+9)(16x^2-9)=0 are x=0,x=-9/2 ,x=-3/4 ,x= 3/4

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2 x (2 x + 9) (16 x^{2} - 9) = 0

x = 0, x = - \frac{9}{2}, x = - \frac{3}{4}, x = \frac{3}{4}

Decimal Notation

x = 0, x = - 4.5, x = - 0.75, x = 0.75

Solution steps

2 x (2 x + 9) (16 x^{2} - 9) = 0

Factor

2 x (2 x + 9) (16 x^{2} - 9) : 2 x (2 x + 9) (4 x + 3) (4 x - 3)

2 x (2 x + 9) (4 x + 3) (4 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 9 = 0 or 4 x + 3 = 0 or 4 x - 3 = 0

Solve

2 x + 9 = 0 : x = - \frac{9}{2}

Solve

4 x + 3 = 0 : x = - \frac{3}{4}

Solve

4 x - 3 = 0 : x = \frac{3}{4}

The solutions are

x = 0, x = - \frac{9}{2}, x = - \frac{3}{4}, x = \frac{3}{4}

x^{4} + x^{3} - x^{2} - x = 0

x^{3} - 2 x^{2} + 2 = 0

9 x^{4} = 36 x^{2}

a^{3} - 4 a^{2} + 4 a = 0

x^{3} - 6 x^{2} - 9 x + 54 = 0

What are the solutions to the equation 2x(2x+9)(16x^2-9)=0 ?
The solutions to the equation 2x(2x+9)(16x^2-9)=0 are x=0,x=-9/2 ,x=-3/4 ,x= 3/4
Find the zeros of 2x(2x+9)(16x^2-9)=0
The zeros of 2x(2x+9)(16x^2-9)=0 are x=0,x=-9/2 ,x=-3/4 ,x= 3/4