What are the solutions to the equation a^3-4a^2+4a=0 ?

The solutions to the equation a^3-4a^2+4a=0 are a=0,a=2

Find the zeros of a^3-4a^2+4a=0

The zeros of a^3-4a^2+4a=0 are a=0,a=2

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a^{3} - 4 a^{2} + 4 a = 0

a = 0, a = 2

Solution steps

a^{3} - 4 a^{2} + 4 a = 0

Factor

a^{3} - 4 a^{2} + 4 a : a (a - 2)^{2}

a (a - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a = 0 or a - 2 = 0

Solve

a - 2 = 0 : a = 2

The solutions are

a = 0, a = 2

x^{3} - 6 x^{2} - 9 x + 54 = 0

(x^{2} + 4)^{2} = 0

e = (m^{8}) 3 m^{21}

3 x^{3} + 4 x^{2} - 7 x + 2 = 0

2 x^{2} + 15 x = x^{3}

What are the solutions to the equation a^3-4a^2+4a=0 ?
The solutions to the equation a^3-4a^2+4a=0 are a=0,a=2
Find the zeros of a^3-4a^2+4a=0
The zeros of a^3-4a^2+4a=0 are a=0,a=2