What are the solutions to the equation x^3+7x^2-5x-35=0 ?

The solutions to the equation x^3+7x^2-5x-35=0 are x=-7,x=-sqrt(5),x=sqrt(5)

Find the zeros of x^3+7x^2-5x-35=0

The zeros of x^3+7x^2-5x-35=0 are x=-7,x=-sqrt(5),x=sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} + 7 x^{2} - 5 x - 35 = 0

x = - 7, x = - 5, x = 5

Decimal Notation

x = - 7, x = - 2.23606 \dots, x = 2.23606 \dots

Solution steps

x^{3} + 7 x^{2} - 5 x - 35 = 0

Factor

x^{3} + 7 x^{2} - 5 x - 35 : (x + 7) (x + 5) (x - 5)

(x + 7) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 7 = 0 or x + 5 = 0 or x - 5 = 0

Solve

x + 7 = 0 : x = - 7

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = - 7, x = - 5, x = 5

x, y^{2} = C x^{3} + 1

h^{4} + 9 = 10 h^{2}

- 3 (36 x^{2} - 25) (x^{2} + 1) = 0

- 2 (x + 8) (25 x^{2} - 49) = 0

k^{3} + 30 k = - 13 k^{2}

What are the solutions to the equation x^3+7x^2-5x-35=0 ?
The solutions to the equation x^3+7x^2-5x-35=0 are x=-7,x=-sqrt(5),x=sqrt(5)
Find the zeros of x^3+7x^2-5x-35=0
The zeros of x^3+7x^2-5x-35=0 are x=-7,x=-sqrt(5),x=sqrt(5)