What are the solutions to the equation 12x^3+20x^2-27x-45=0 ?

The solutions to the equation 12x^3+20x^2-27x-45=0 are x=-5/3 ,x=-3/2 ,x= 3/2

Find the zeros of 12x^3+20x^2-27x-45=0

The zeros of 12x^3+20x^2-27x-45=0 are x=-5/3 ,x=-3/2 ,x= 3/2

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12 x^{3} + 20 x^{2} - 27 x - 45 = 0

x = - \frac{5}{3}, x = - \frac{3}{2}, x = \frac{3}{2}

Decimal Notation

x = - 1.66666 \dots, x = - 1.5, x = 1.5

Solution steps

12 x^{3} + 20 x^{2} - 27 x - 45 = 0

Factor

12 x^{3} + 20 x^{2} - 27 x - 45 : (3 x + 5) (2 x + 3) (2 x - 3)

(3 x + 5) (2 x + 3) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 5 = 0 or 2 x + 3 = 0 or 2 x - 3 = 0

Solve

3 x + 5 = 0 : x = - \frac{5}{3}

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = - \frac{5}{3}, x = - \frac{3}{2}, x = \frac{3}{2}

2 x (x^{2} + 2 x - 6) = 0

x^{3} + 6 x^{2} + x - 34 = 0

6 = - w^{8}

a^{3} + 1 = 0

x^{3} - 4 x^{2} - 5 x + 20 = 0

What are the solutions to the equation 12x^3+20x^2-27x-45=0 ?
The solutions to the equation 12x^3+20x^2-27x-45=0 are x=-5/3 ,x=-3/2 ,x= 3/2
Find the zeros of 12x^3+20x^2-27x-45=0
The zeros of 12x^3+20x^2-27x-45=0 are x=-5/3 ,x=-3/2 ,x= 3/2