What are the solutions to the equation x^3-4x^2-5x+20=0 ?

The solutions to the equation x^3-4x^2-5x+20=0 are x=4,x=-sqrt(5),x=sqrt(5)

Find the zeros of x^3-4x^2-5x+20=0

The zeros of x^3-4x^2-5x+20=0 are x=4,x=-sqrt(5),x=sqrt(5)

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x^{3} - 4 x^{2} - 5 x + 20 = 0

x = 4, x = - 5, x = 5

Decimal Notation

x = 4, x = - 2.23606 \dots, x = 2.23606 \dots

Solution steps

x^{3} - 4 x^{2} - 5 x + 20 = 0

Factor

x^{3} - 4 x^{2} - 5 x + 20 : (x - 4) (x + 5) (x - 5)

(x - 4) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 5 = 0 or x - 5 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = 4, x = - 5, x = 5

- x^{3} + 3 x + 1 = 0

x^{3} - 7 x^{2} + 4 x - 28 = 0

x^{4} - 21 x^{2} + 80 = 0

(\frac{4 x - 7}{3})^{3} = 27

x^{3} + 5 x^{2} = - 6 x

What are the solutions to the equation x^3-4x^2-5x+20=0 ?
The solutions to the equation x^3-4x^2-5x+20=0 are x=4,x=-sqrt(5),x=sqrt(5)
Find the zeros of x^3-4x^2-5x+20=0
The zeros of x^3-4x^2-5x+20=0 are x=4,x=-sqrt(5),x=sqrt(5)