What are the solutions to the equation x^3-4bx^2-9x+36b=0 ?

The solutions to the equation x^3-4bx^2-9x+36b=0 are x=4b,x=-3,x=3

Find the zeros of x^3-4bx^2-9x+36b=0

The zeros of x^3-4bx^2-9x+36b=0 are x=4b,x=-3,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 4 b x^{2} - 9 x + 36 b = 0

x = 4 b, x = - 3, x = 3

Solution steps

x^{3} - 4 b x^{2} - 9 x + 36 b = 0

Factor

x^{3} - 4 b x^{2} - 9 x + 36 b : (x - 4 b) (x + 3) (x - 3)

(x - 4 b) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 b = 0 or x + 3 = 0 or x - 3 = 0

Solve

x - 4 b = 0 : x = 4 b

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 4 b, x = - 3, x = 3

- x^{3} - x^{2} - x - 1 = 0

x^{4} - 6 x^{2} = - 8

x^{3} - 19 x + 30 = 0

8 x^{5} + 2 x^{4} - 3 x^{3} = 0

25 x^{3} - 16 x = 0

What are the solutions to the equation x^3-4bx^2-9x+36b=0 ?
The solutions to the equation x^3-4bx^2-9x+36b=0 are x=4b,x=-3,x=3
Find the zeros of x^3-4bx^2-9x+36b=0
The zeros of x^3-4bx^2-9x+36b=0 are x=4b,x=-3,x=3