What are the solutions to the equation (2x-b)(4x^2-8x+3)=0 ?

The solutions to the equation (2x-b)(4x^2-8x+3)=0 are x= b/2 ,x= 1/2 ,x= 3/2

Find the zeros of (2x-b)(4x^2-8x+3)=0

The zeros of (2x-b)(4x^2-8x+3)=0 are x= b/2 ,x= 1/2 ,x= 3/2

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(2 x - b) (4 x^{2} - 8 x + 3) = 0

x = \frac{b}{2}, x = \frac{1}{2}, x = \frac{3}{2}

Solution steps

(2 x - b) (4 x^{2} - 8 x + 3) = 0

Factor

(2 x - b) (4 x^{2} - 8 x + 3) : (2 x - b) (2 x - 1) (2 x - 3)

(2 x - b) (2 x - 1) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - b = 0 or 2 x - 1 = 0 or 2 x - 3 = 0

Solve

2 x - b = 0 : x = \frac{b}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = \frac{b}{2}, x = \frac{1}{2}, x = \frac{3}{2}

- x^{3} - 3 x^{2} - 3 x - 1 = 0

z^{4} + 16 z^{2} - 225 = 0

x^{6} - x^{2} = 0

x, x^{3} - 64 = 0

- r^{3} + 4 r^{2} - 6 r + 4 = 0

What are the solutions to the equation (2x-b)(4x^2-8x+3)=0 ?
The solutions to the equation (2x-b)(4x^2-8x+3)=0 are x= b/2 ,x= 1/2 ,x= 3/2
Find the zeros of (2x-b)(4x^2-8x+3)=0
The zeros of (2x-b)(4x^2-8x+3)=0 are x= b/2 ,x= 1/2 ,x= 3/2