What are the solutions to the equation (x^3-3x^2)-(2x-6)=0 ?

The solutions to the equation (x^3-3x^2)-(2x-6)=0 are x=3,x=-sqrt(2),x=sqrt(2)

Find the zeros of (x^3-3x^2)-(2x-6)=0

The zeros of (x^3-3x^2)-(2x-6)=0 are x=3,x=-sqrt(2),x=sqrt(2)

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(x^{3} - 3 x^{2}) - (2 x - 6) = 0

x = 3, x = - 2, x = 2

Decimal Notation

x = 3, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

(x^{3} - 3 x^{2}) - (2 x - 6) = 0

Factor

(x^{3} - 3 x^{2}) - (2 x - 6) : (x - 3) (x + 2) (x - 2)

(x - 3) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 3, x = - 2, x = 2

x^{4} - 2 x^{3} - 13 x^{2} + 14 x + 24 = 0

y - y^{4} = 0

900 (1 - d)^{3} = 200

x^{4} - 2 x^{2} + x = 0

x^{3} - 5 x^{2} + 4 = 0

What are the solutions to the equation (x^3-3x^2)-(2x-6)=0 ?
The solutions to the equation (x^3-3x^2)-(2x-6)=0 are x=3,x=-sqrt(2),x=sqrt(2)
Find the zeros of (x^3-3x^2)-(2x-6)=0
The zeros of (x^3-3x^2)-(2x-6)=0 are x=3,x=-sqrt(2),x=sqrt(2)