What are the solutions to the equation x^2-11x+24=0 ?

The solutions to the equation x^2-11x+24=0 are x=8,x=3

Find the zeros of x^2-11x+24=0

The zeros of x^2-11x+24=0 are x=8,x=3

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x^{2} - 11 x + 24 = 0

x = 8, x = 3

Solution steps

x^{2} - 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- ( - 11 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 5}{2 \cdot 1}

x = \frac{- ( - 11 ) + 5}{2 \cdot 1} : 8

x = \frac{- ( - 11 ) - 5}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 8, x = 3

(c^{3})^{2} (- 3 c^{5})^{2}

\frac{8 !}{2 ! 6 !}

6^{2} + b^{2} = (62)^{2}

\frac{4}{10} x - 3 x + \frac{8}{5} = \frac{4}{5}

x + \frac{1}{3} = \frac{x}{3}

What are the solutions to the equation x^2-11x+24=0 ?
The solutions to the equation x^2-11x+24=0 are x=8,x=3
Find the zeros of x^2-11x+24=0
The zeros of x^2-11x+24=0 are x=8,x=3