What are the solutions to the equation (x+3a)(2x^2-11x+12)=0 ?

The solutions to the equation (x+3a)(2x^2-11x+12)=0 are x=-3a,x= 3/2 ,x=4

Find the zeros of (x+3a)(2x^2-11x+12)=0

The zeros of (x+3a)(2x^2-11x+12)=0 are x=-3a,x= 3/2 ,x=4

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(x + 3 a) (2 x^{2} - 11 x + 12) = 0

x = - 3 a, x = \frac{3}{2}, x = 4

Solution steps

(x + 3 a) (2 x^{2} - 11 x + 12) = 0

Factor

(x + 3 a) (2 x^{2} - 11 x + 12) : (x + 3 a) (2 x - 3) (x - 4)

(x + 3 a) (2 x - 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 a = 0 or 2 x - 3 = 0 or x - 4 = 0

Solve

x + 3 a = 0 : x = - 3 a

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 3 a, x = \frac{3}{2}, x = 4

x^{3} + x^{2} - 4 x + 4 = 0

2 x^{3} - 2 x - 5 = 0

12 x^{4} = 3 x^{2}

8 x^{3} = 27

x^{3} + 6 x^{2} - 16 x - 96 = 0

What are the solutions to the equation (x+3a)(2x^2-11x+12)=0 ?
The solutions to the equation (x+3a)(2x^2-11x+12)=0 are x=-3a,x= 3/2 ,x=4
Find the zeros of (x+3a)(2x^2-11x+12)=0
The zeros of (x+3a)(2x^2-11x+12)=0 are x=-3a,x= 3/2 ,x=4