What are the solutions to the equation (7-11x)(x^2+7x+12)=0 ?

The solutions to the equation (7-11x)(x^2+7x+12)=0 are x=-3,x=-4,x= 7/11

Find the zeros of (7-11x)(x^2+7x+12)=0

The zeros of (7-11x)(x^2+7x+12)=0 are x=-3,x=-4,x= 7/11

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(7 - 11 x) (x^{2} + 7 x + 12) = 0

x = - 3, x = - 4, x = \frac{7}{11}

Decimal Notation

x = - 3, x = - 4, x = 0.63636 \dots

Solution steps

(7 - 11 x) (x^{2} + 7 x + 12) = 0

Factor

(7 - 11 x) (x^{2} + 7 x + 12) : - (x + 3) (x + 4) (11 x - 7)

- (x + 3) (x + 4) (11 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 4 = 0 or 11 x - 7 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 4 = 0 : x = - 4

Solve

11 x - 7 = 0 : x = \frac{7}{11}

The solutions are

x = - 3, x = - 4, x = \frac{7}{11}

(x^{2} - 7)^{2} + (x^{2} - 7) = 6

x^{3} - 12 x^{2} + 20 x = 0

x^{4} - 12 x^{2} + 11 = 0

2 x (x - 5) (x + 8) = 0

x^{5} + 4 x^{3} = 0

What are the solutions to the equation (7-11x)(x^2+7x+12)=0 ?
The solutions to the equation (7-11x)(x^2+7x+12)=0 are x=-3,x=-4,x= 7/11
Find the zeros of (7-11x)(x^2+7x+12)=0
The zeros of (7-11x)(x^2+7x+12)=0 are x=-3,x=-4,x= 7/11