What are the solutions to the equation r^3=27 ?

The solutions to the equation r^3=27 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i

Find the zeros of r^3=27

The zeros of r^3=27 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{3} = 27

r = 3, r = - \frac{3}{2} + \frac{3 3}{2} i, r = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

r^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

r = 3, r = - \frac{3}{2} + \frac{3 3}{2} i, r = - \frac{3}{2} - \frac{3 3}{2} i

(3 x + 4)^{3} = 2197

x^{3} + 12 x + 2 = 0

- 4 y + 4 y^{3} = 0

x^{3} - 3 = x^{9} + 3

z^{3} = - 2 + 23 i

What are the solutions to the equation r^3=27 ?
The solutions to the equation r^3=27 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i
Find the zeros of r^3=27
The zeros of r^3=27 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i