What are the solutions to the equation x^3+4x+1=0 ?

The solutions to the equation x^3+4x+1=0 are x\approx-0.24626…

Find the zeros of x^3+4x+1=0

The zeros of x^3+4x+1=0 are x\approx-0.24626…

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x^{3} + 4 x + 1 = 0

x \approx - 0.24626 \dots

Solution steps

x^{3} + 4 x + 1 = 0

Find one solution for

x^{3} + 4 x + 1 = 0

using Newton-Raphson:

x \approx - 0.24626 \dots

Apply long division:

\frac{x ^{3} + 4 x + 1}{x + 0.24626 \dots} = x^{2} - 0.24626 \dots x + 4.06064 \dots

x^{2} - 0.24626 \dots x + 4.06064 \dots \approx 0

Find one solution for

x^{2} - 0.24626 \dots x + 4.06064 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 0.24626 \dots

x^{2} - 16 = (x^{4}) (x - 4)

3 x^{3} - 15 x^{2} + 9 x - 5 = 0

108 x + 15 x^{2} - 3 x^{3} = 0

x, x^{3} + y^{2} - 4 y + 4 = 0

(x^{2} + 16 x)^{2} = 1 7^{2}

What are the solutions to the equation x^3+4x+1=0 ?
The solutions to the equation x^3+4x+1=0 are x\approx-0.24626…
Find the zeros of x^3+4x+1=0
The zeros of x^3+4x+1=0 are x\approx-0.24626…