What are the solutions to the equation 2b^3+5=2(3)^3+5 ?

The solutions to the equation 2b^3+5=2(3)^3+5 are b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i

Find the zeros of 2b^3+5=2(3)^3+5

The zeros of 2b^3+5=2(3)^3+5 are b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i

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2 b^{3} + 5 = 2 (3)^{3} + 5

b = 3, b = - \frac{3}{2} + \frac{3 3}{2} i, b = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

2 b^{3} + 5 = 2 (3)^{3} + 5

Expand

2 \cdot 3^{3} + 5 : 59

2 b^{3} + 5 = 59

Move

5

to the right side

2 b^{3} = 54

Divide both sides by

2

b^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

b = 3, b = - \frac{3}{2} + \frac{3 3}{2} i, b = - \frac{3}{2} - \frac{3 3}{2} i

2 - y^{2} = y^{4}

x^{4} = 9 x^{6}

b^{3} = 27

30 x + 27 x^{2} - 3 x^{3} = 0

x (x^{2} - 49) (x^{2} + 81) = 0

What are the solutions to the equation 2b^3+5=2(3)^3+5 ?
The solutions to the equation 2b^3+5=2(3)^3+5 are b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i
Find the zeros of 2b^3+5=2(3)^3+5
The zeros of 2b^3+5=2(3)^3+5 are b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i