What are the solutions to the equation x(x^2-49)(x^2+81)=0 ?

The solutions to the equation x(x^2-49)(x^2+81)=0 are x=0,x=-7,x=7,x=9i,x=-9i

Find the zeros of x(x^2-49)(x^2+81)=0

The zeros of x(x^2-49)(x^2+81)=0 are x=0,x=-7,x=7,x=9i,x=-9i

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x (x^{2} - 49) (x^{2} + 81) = 0

x = 0, x = - 7, x = 7, x = 9 i, x = - 9 i

Solution steps

x (x^{2} - 49) (x^{2} + 81) = 0

Factor

x (x^{2} - 49) (x^{2} + 81) : x (x + 7) (x - 7) (x^{2} + 81)

x (x + 7) (x - 7) (x^{2} + 81) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 7 = 0 or x - 7 = 0 or x^{2} + 81 = 0

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

Solve

x^{2} + 81 = 0 : x = 9 i, x = - 9 i

The solutions are

x = 0, x = - 7, x = 7, x = 9 i, x = - 9 i

x^{6} - 56 x^{3} - 512 = 0

x^{3} - x^{2} - 17 x - 15 = 0

18 y^{3} = 50 y

x^{4} - x - 12 = 0

3 (x^{2} + 3 x - 10) (x - 8) = 0

What are the solutions to the equation x(x^2-49)(x^2+81)=0 ?
The solutions to the equation x(x^2-49)(x^2+81)=0 are x=0,x=-7,x=7,x=9i,x=-9i
Find the zeros of x(x^2-49)(x^2+81)=0
The zeros of x(x^2-49)(x^2+81)=0 are x=0,x=-7,x=7,x=9i,x=-9i