What are the solutions to the equation b^3=27 ?

The solutions to the equation b^3=27 are b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i

Find the zeros of b^3=27

The zeros of b^3=27 are b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i

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b^{3} = 27

b = 3, b = - \frac{3}{2} + \frac{3 3}{2} i, b = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

b^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

b = 3, b = - \frac{3}{2} + \frac{3 3}{2} i, b = - \frac{3}{2} - \frac{3 3}{2} i

30 x + 27 x^{2} - 3 x^{3} = 0

x (x^{2} - 49) (x^{2} + 81) = 0

x^{6} - 56 x^{3} - 512 = 0

x^{3} - x^{2} - 17 x - 15 = 0

18 y^{3} = 50 y

What are the solutions to the equation b^3=27 ?
The solutions to the equation b^3=27 are b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i
Find the zeros of b^3=27
The zeros of b^3=27 are b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i