What are the solutions to the equation 2x^3-18x^2-8x+72=0 ?

The solutions to the equation 2x^3-18x^2-8x+72=0 are x=9,x=-2,x=2

Find the zeros of 2x^3-18x^2-8x+72=0

The zeros of 2x^3-18x^2-8x+72=0 are x=9,x=-2,x=2

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2 x^{3} - 18 x^{2} - 8 x + 72 = 0

x = 9, x = - 2, x = 2

Solution steps

2 x^{3} - 18 x^{2} - 8 x + 72 = 0

Factor

2 x^{3} - 18 x^{2} - 8 x + 72 : 2 (x - 9) (x + 2) (x - 2)

2 (x - 9) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 9 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 9 = 0 : x = 9

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 9, x = - 2, x = 2

(x + 7) (x^{2} - 49) = 0

16 x^{4} + 9 = 25 x^{2}

x^{3} - 3 x - 7 = 0

4 x^{4} - 5 x^{2} + 4 = 0

r^{3} - 3 r^{2} + 3 r - 1 = 0

What are the solutions to the equation 2x^3-18x^2-8x+72=0 ?
The solutions to the equation 2x^3-18x^2-8x+72=0 are x=9,x=-2,x=2
Find the zeros of 2x^3-18x^2-8x+72=0
The zeros of 2x^3-18x^2-8x+72=0 are x=9,x=-2,x=2