What are the solutions to the equation -3(x^2-16)(25x^2-36)=0 ?

The solutions to the equation -3(x^2-16)(25x^2-36)=0 are x=-4,x=4,x=-6/5 ,x= 6/5

Find the zeros of -3(x^2-16)(25x^2-36)=0

The zeros of -3(x^2-16)(25x^2-36)=0 are x=-4,x=4,x=-6/5 ,x= 6/5

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- 3 (x^{2} - 16) (25 x^{2} - 36) = 0

x = - 4, x = 4, x = - \frac{6}{5}, x = \frac{6}{5}

Decimal Notation

x = - 4, x = 4, x = - 1.2, x = 1.2

Solution steps

- 3 (x^{2} - 16) (25 x^{2} - 36) = 0

Factor

- 3 (x^{2} - 16) (25 x^{2} - 36) : - 3 (x + 4) (x - 4) (5 x + 6) (5 x - 6)

- 3 (x + 4) (x - 4) (5 x + 6) (5 x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x - 4 = 0 or 5 x + 6 = 0 or 5 x - 6 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 4 = 0 : x = 4

Solve

5 x + 6 = 0 : x = - \frac{6}{5}

Solve

5 x - 6 = 0 : x = \frac{6}{5}

The solutions are

x = - 4, x = 4, x = - \frac{6}{5}, x = \frac{6}{5}

- x^{3} - 3 x^{2} + x + 3 = 0

a = (x - 3)^{10} + 1

x^{3} - 3 x^{2} - 18 x = 0

x, x^{4} + 2 x^{2} y^{2} = 0

x (x + 1) (x + 2) = 63 (x + 1)

What are the solutions to the equation -3(x^2-16)(25x^2-36)=0 ?
The solutions to the equation -3(x^2-16)(25x^2-36)=0 are x=-4,x=4,x=-6/5 ,x= 6/5
Find the zeros of -3(x^2-16)(25x^2-36)=0
The zeros of -3(x^2-16)(25x^2-36)=0 are x=-4,x=4,x=-6/5 ,x= 6/5