What are the solutions to the equation 2(64x^2-25)(x^2+49)=0 ?

The solutions to the equation 2(64x^2-25)(x^2+49)=0 are x=-5/8 ,x= 5/8 ,x=7i,x=-7i

Find the zeros of 2(64x^2-25)(x^2+49)=0

The zeros of 2(64x^2-25)(x^2+49)=0 are x=-5/8 ,x= 5/8 ,x=7i,x=-7i

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2 (64 x^{2} - 25) (x^{2} + 49) = 0

x = - \frac{5}{8}, x = \frac{5}{8}, x = 7 i, x = - 7 i

Solution steps

2 (64 x^{2} - 25) (x^{2} + 49) = 0

Factor

2 (64 x^{2} - 25) (x^{2} + 49) : 2 (8 x + 5) (8 x - 5) (x^{2} + 49)

2 (8 x + 5) (8 x - 5) (x^{2} + 49) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

8 x + 5 = 0 or 8 x - 5 = 0 or x^{2} + 49 = 0

Solve

8 x + 5 = 0 : x = - \frac{5}{8}

Solve

8 x - 5 = 0 : x = \frac{5}{8}

Solve

x^{2} + 49 = 0 : x = 7 i, x = - 7 i

The solutions are

x = - \frac{5}{8}, x = \frac{5}{8}, x = 7 i, x = - 7 i

- x^{4} + 1 = 2 x^{2} - 3

f^{4} - 4 f^{3} = 25 f

x^{4} - 5 x^{3} - 7 x^{2} + 29 x = - 30

n^{3} = 2 n

x^{3} + 2 x = 400

What are the solutions to the equation 2(64x^2-25)(x^2+49)=0 ?
The solutions to the equation 2(64x^2-25)(x^2+49)=0 are x=-5/8 ,x= 5/8 ,x=7i,x=-7i
Find the zeros of 2(64x^2-25)(x^2+49)=0
The zeros of 2(64x^2-25)(x^2+49)=0 are x=-5/8 ,x= 5/8 ,x=7i,x=-7i