What are the solutions to the equation (4-x^2)^2=0 ?

The solutions to the equation (4-x^2)^2=0 are x=2,x=-2

Find the zeros of (4-x^2)^2=0

The zeros of (4-x^2)^2=0 are x=2,x=-2

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(4 - x^{2})^{2} = 0

x = 2, x = - 2

Solution steps

(4 - x^{2})^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

4 - x^{2} = 0 : x = 2, x = - 2

The solutions are

x = 2, x = - 2

d^{4} - 81 = 0

x^{6} + 3 x^{3} - 4 = 0

2 x^{4} + 3 x^{2} - 20 = 0

x^{4} - 2 x^{2} - 15 = 0

λ^{3} + 2 λ^{2} - λ - 2 = 0

What are the solutions to the equation (4-x^2)^2=0 ?
The solutions to the equation (4-x^2)^2=0 are x=2,x=-2
Find the zeros of (4-x^2)^2=0
The zeros of (4-x^2)^2=0 are x=2,x=-2