What are the solutions to the equation y^3=-1 ?

The solutions to the equation y^3=-1 are y=-1,y= 1/2-(sqrt(3))/2 i,y= 1/2+(sqrt(3))/2 i

Find the zeros of y^3=-1

The zeros of y^3=-1 are y=-1,y= 1/2-(sqrt(3))/2 i,y= 1/2+(sqrt(3))/2 i

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y^{3} = - 1

y = - 1, y = \frac{1}{2} - \frac{3}{2} i, y = \frac{1}{2} + \frac{3}{2} i

Solution steps

y^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

y = - 1, y = \frac{1}{2} - \frac{3}{2} i, y = \frac{1}{2} + \frac{3}{2} i

y^{3} = - 8

x^{3} - x^{2} - 2 = 3

x^{3} - 3 x - 2.2 = 0

x^{3} - 4 x^{2} - 10 x + 40 = 0

x^{3} + 5 x^{2} + 4 x + 4 = 0

What are the solutions to the equation y^3=-1 ?
The solutions to the equation y^3=-1 are y=-1,y= 1/2-(sqrt(3))/2 i,y= 1/2+(sqrt(3))/2 i
Find the zeros of y^3=-1
The zeros of y^3=-1 are y=-1,y= 1/2-(sqrt(3))/2 i,y= 1/2+(sqrt(3))/2 i