What are the solutions to the equation y^4-6y^2+8=0 ?

The solutions to the equation y^4-6y^2+8=0 are y=2,y=-2,y=sqrt(2),y=-sqrt(2)

Find the zeros of y^4-6y^2+8=0

The zeros of y^4-6y^2+8=0 are y=2,y=-2,y=sqrt(2),y=-sqrt(2)

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y^{4} - 6 y^{2} + 8 = 0

y = 2, y = - 2, y = 2, y = - 2

Decimal Notation

y = 2, y = - 2, y = 1.41421 \dots, y = - 1.41421 \dots

Solution steps

y^{4} - 6 y^{2} + 8 = 0

Rewrite the equation with

u = y^{2}

and

u^{2} = y^{4}

u^{2} - 6 u + 8 = 0

Solve

u^{2} - 6 u + 8 = 0 : u = 4, u = 2

u = 4, u = 2

Substitute back

u = y^{2},

solve for

y

Solve

y^{2} = 4 : y = 2, y = - 2

Solve

y^{2} = 2 : y = 2, y = - 2

The solutions are

y = 2, y = - 2, y = 2, y = - 2

20000 = 5000 (1 + \frac{x}{2})^{20}

- x^{3} + 2 x^{2} - x - 2 = 0

x^{4} - 12 x^{2} + 20 = 0

x^{3} - 4 x^{2} + 8 = 0

x^{3} + 5 x^{2} + 2 x + 10 = 0

What are the solutions to the equation y^4-6y^2+8=0 ?
The solutions to the equation y^4-6y^2+8=0 are y=2,y=-2,y=sqrt(2),y=-sqrt(2)
Find the zeros of y^4-6y^2+8=0
The zeros of y^4-6y^2+8=0 are y=2,y=-2,y=sqrt(2),y=-sqrt(2)