What are the solutions to the equation 20000=5000(1+x/2)^{20} ?

The solutions to the equation 20000=5000(1+x/2)^{20} are x=2\sqrt[10]{2}-2,x=-2\sqrt[10]{2}-2

Find the zeros of 20000=5000(1+x/2)^{20}

The zeros of 20000=5000(1+x/2)^{20} are x=2\sqrt[10]{2}-2,x=-2\sqrt[10]{2}-2

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20000 = 5000 (1 + \frac{x}{2})^{20}

Solution steps

20000 = 5000 (1 + \frac{x}{2})^{20}

Switch sides

5000 (1 + \frac{x}{2})^{20} = 20000

Divide both sides by

5000

(1 + \frac{x}{2})^{20} = 4

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

- x^{3} + 2 x^{2} - x - 2 = 0

x^{4} - 12 x^{2} + 20 = 0

x^{3} - 4 x^{2} + 8 = 0

x^{3} + 5 x^{2} + 2 x + 10 = 0

- x (6 x + 7) (x^{2} - 36) = 0

What are the solutions to the equation 20000=5000(1+x/2)^{20} ?
The solutions to the equation 20000=5000(1+x/2)^{20} are x=2\sqrt[10]{2}-2,x=-2\sqrt[10]{2}-2
Find the zeros of 20000=5000(1+x/2)^{20}
The zeros of 20000=5000(1+x/2)^{20} are x=2\sqrt[10]{2}-2,x=-2\sqrt[10]{2}-2