What are the solutions to the equation 4x^3+5x^2+36x+45=0 ?

The solutions to the equation 4x^3+5x^2+36x+45=0 are x=-5/4 ,x=3i,x=-3i

Find the zeros of 4x^3+5x^2+36x+45=0

The zeros of 4x^3+5x^2+36x+45=0 are x=-5/4 ,x=3i,x=-3i

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4 x^{3} + 5 x^{2} + 36 x + 45 = 0

x = - \frac{5}{4}, x = 3 i, x = - 3 i

Solution steps

4 x^{3} + 5 x^{2} + 36 x + 45 = 0

Factor

4 x^{3} + 5 x^{2} + 36 x + 45 : (4 x + 5) (x^{2} + 9)

(4 x + 5) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 5 = 0 or x^{2} + 9 = 0

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = - \frac{5}{4}, x = 3 i, x = - 3 i

- h^{3} - 4 = 13

x^{5} + x = 1

- 35 x^{6} = (- 5 x^{2}) (B)

x^{3} - 7 x^{2} - 49 x + 343 = 0

3 x^{3} + 2 x^{2} + 27 x + 18 = 0

What are the solutions to the equation 4x^3+5x^2+36x+45=0 ?
The solutions to the equation 4x^3+5x^2+36x+45=0 are x=-5/4 ,x=3i,x=-3i
Find the zeros of 4x^3+5x^2+36x+45=0
The zeros of 4x^3+5x^2+36x+45=0 are x=-5/4 ,x=3i,x=-3i