What are the solutions to the equation 3x^3+2x^2+27x+18=0 ?

The solutions to the equation 3x^3+2x^2+27x+18=0 are x=-2/3 ,x=3i,x=-3i

Find the zeros of 3x^3+2x^2+27x+18=0

The zeros of 3x^3+2x^2+27x+18=0 are x=-2/3 ,x=3i,x=-3i

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3 x^{3} + 2 x^{2} + 27 x + 18 = 0

x = - \frac{2}{3}, x = 3 i, x = - 3 i

Solution steps

3 x^{3} + 2 x^{2} + 27 x + 18 = 0

Factor

3 x^{3} + 2 x^{2} + 27 x + 18 : (3 x + 2) (x^{2} + 9)

(3 x + 2) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or x^{2} + 9 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = - \frac{2}{3}, x = 3 i, x = - 3 i

4 x^{3} - 12 x^{2} + 6 x = 0

(- 2 x^{2} - 5 x + 3) (3 a + x) = 0

a^{3} = 78

x^{4} - 6 x^{3} + 14 x^{2} - 14 x + 5 = 0

3 x^{5} - 20 x^{3} = 0

What are the solutions to the equation 3x^3+2x^2+27x+18=0 ?
The solutions to the equation 3x^3+2x^2+27x+18=0 are x=-2/3 ,x=3i,x=-3i
Find the zeros of 3x^3+2x^2+27x+18=0
The zeros of 3x^3+2x^2+27x+18=0 are x=-2/3 ,x=3i,x=-3i