What are the solutions to the equation (-2x^2-5x+3)(3a+x)=0 ?

The solutions to the equation (-2x^2-5x+3)(3a+x)=0 are x= 1/2 ,x=-3,x=-3a

Find the zeros of (-2x^2-5x+3)(3a+x)=0

The zeros of (-2x^2-5x+3)(3a+x)=0 are x= 1/2 ,x=-3,x=-3a

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(- 2 x^{2} - 5 x + 3) (3 a + x) = 0

x = \frac{1}{2}, x = - 3, x = - 3 a

Solution steps

(- 2 x^{2} - 5 x + 3) (3 a + x) = 0

Factor

(- 2 x^{2} - 5 x + 3) (3 a + x) : - (2 x - 1) (x + 3) (3 a + x)

- (2 x - 1) (x + 3) (3 a + x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 3 = 0 or 3 a + x = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 3 = 0 : x = - 3

Solve

3 a + x = 0 : x = - 3 a

The solutions are

x = \frac{1}{2}, x = - 3, x = - 3 a

a^{3} = 78

x^{4} - 6 x^{3} + 14 x^{2} - 14 x + 5 = 0

3 x^{5} - 20 x^{3} = 0

3 x^{3} + x^{2} - 8 x + 4 = 0

(X - 2) (X + 4) (X - 5) = 0

What are the solutions to the equation (-2x^2-5x+3)(3a+x)=0 ?
The solutions to the equation (-2x^2-5x+3)(3a+x)=0 are x= 1/2 ,x=-3,x=-3a
Find the zeros of (-2x^2-5x+3)(3a+x)=0
The zeros of (-2x^2-5x+3)(3a+x)=0 are x= 1/2 ,x=-3,x=-3a