What are the solutions to the equation -3x(x+9)(x^2+1)=0 ?

The solutions to the equation -3x(x+9)(x^2+1)=0 are x=0,x=-9,x=i,x=-i

Find the zeros of -3x(x+9)(x^2+1)=0

The zeros of -3x(x+9)(x^2+1)=0 are x=0,x=-9,x=i,x=-i

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- 3 x (x + 9) (x^{2} + 1) = 0

x = 0, x = - 9, x = i, x = - i

Solution steps

- 3 x (x + 9) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 9 = 0 or x^{2} + 1 = 0

Solve

x + 9 = 0 : x = - 9

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = 0, x = - 9, x = i, x = - i

16 z^{4} - 4 z^{2} + 1 = 0

5 x^{3} - 27 x^{2} - 17 x - 6 = 0

5 x^{5} - 45 x = 0

- x^{4} - 8 x^{3} + 7 x^{2} + 56 x = 0

x^{4} - 32 x^{2} + 256 = 0

What are the solutions to the equation -3x(x+9)(x^2+1)=0 ?
The solutions to the equation -3x(x+9)(x^2+1)=0 are x=0,x=-9,x=i,x=-i
Find the zeros of -3x(x+9)(x^2+1)=0
The zeros of -3x(x+9)(x^2+1)=0 are x=0,x=-9,x=i,x=-i