What are the solutions to the equation x(x+4)(x-1)=0 ?

The solutions to the equation x(x+4)(x-1)=0 are x=0,x=-4,x=1

Find the zeros of x(x+4)(x-1)=0

The zeros of x(x+4)(x-1)=0 are x=0,x=-4,x=1

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x (x + 4) (x - 1) = 0

x = 0, x = - 4, x = 1

Solution steps

x (x + 4) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 4 = 0 or x - 1 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = - 4, x = 1

x^{3} - 49 x + 120 = 0

- x^{3} + 12 x^{2} - 21 x + 10 = 0

27 x^{3} - 512 = 0

y^{3} + y^{2} = 81 y + 81

18 q - 21 q^{2} + 6 q^{3} = 0

What are the solutions to the equation x(x+4)(x-1)=0 ?
The solutions to the equation x(x+4)(x-1)=0 are x=0,x=-4,x=1
Find the zeros of x(x+4)(x-1)=0
The zeros of x(x+4)(x-1)=0 are x=0,x=-4,x=1