What are the solutions to the equation x^3-9x^2+24x-16=0 ?

The solutions to the equation x^3-9x^2+24x-16=0 are x=1,x=4

Find the zeros of x^3-9x^2+24x-16=0

The zeros of x^3-9x^2+24x-16=0 are x=1,x=4

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x^{3} - 9 x^{2} + 24 x - 16 = 0

x = 1, x = 4

Solution steps

x^{3} - 9 x^{2} + 24 x - 16 = 0

Factor

x^{3} - 9 x^{2} + 24 x - 16 : (x - 1) (x - 4)^{2}

(x - 1) (x - 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 4 = 0 : x = 4

The solutions are

x = 1, x = 4

2 x^{3} = (x - 1)^{3}

16 x = 2 x^{4}

- 3 x (2 x - 5) (x^{2} + 25) = 0

3 x^{2} = x^{4}

x^{6} - 7 x^{3} = 8

What are the solutions to the equation x^3-9x^2+24x-16=0 ?
The solutions to the equation x^3-9x^2+24x-16=0 are x=1,x=4
Find the zeros of x^3-9x^2+24x-16=0
The zeros of x^3-9x^2+24x-16=0 are x=1,x=4